• Computes 1 % 3, which is 1
• Computes "" + 1, which is "1"
• Creates dig and sets it to point to "1"
• Checks if 1 / 3, which is 0, is > 0, which is false
• Stops and returns "1"

Resulting call stack

r(1)  returns "1"
r(3)     dig -> "0"    "0" + ____
r(10)    dig -> "1"    "1" + ____
r(32)    dig -> "2"    "2" + ____

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